Solution 6 to problem over
Expressions |
Parameters |
Inequalities |
Relevance |
Back to problem over
Expressions
The solution is given through the following expressions:
r40=0
r41=0
r42=0
r43=0
r44=0
r45=0
r46=0
r47=0
r48=0
r49=0
r410=0
r411=0
r412=0
r413=0
r418=0
r421=0
r423=0
r424=0
1
r427=---*r494
2
r429=0
1
r430=---*r494
2
r432=0
r433=0
r435=0
r436=0
r437=0
r438=0
r439=0
r440=0
r441=0
r442=0
r443=0
r444=0
r447=0
r449=0
r450=0
r452=0
r453= - r487
r454=0
r455=0
r456=0
1
r457=---*r494
2
r458=0
r459=0
r460=0
r462=0
r463=0
1
a11*r487 + ---*b12*kap*r494
2
r464=-----------------------------
b12
r465=0
r466=0
r467=0
r468=0
r469=0
r470=0
r471=0
r472=0
r473=0
r474=0
r475=0
r476=0
r477=0
r479=0
r482=0
r484=0
r485=0
r488=0
r489=0
r490=0
r491=0
r492=0
r493=0
r495=0
r497=0
r498=0
r499=0
r4100=0
r4101=0
r4102=0
r4103=0
r4104=0
r4105=0
r4106=0
r4108=0
r4109=0
1
r4110=---*r494
2
r4112=0
r4113=0
1
a11*r487 + ---*b12*kap*r494
2
r4114=-----------------------------
b12
r4115=0
r4116=0
r4117=0
r4118=0
r4119=0
r4120=0
r4121=0
r4122=0
r4123=0
r4124=0
r4125=0
a23=0
a22=a11
a13=0
Parameters
Apart from the condition that they must not vanish to give
a non-trivial solution and a non-singular solution with
non-vanishing denominators, the following parameters are free:
r434, r487, r494, a11, a33, b12
Inequalities
In the following not identically vanishing expressions are shown.
Any auxiliary variables g00?? are used to express that at least
one of their coefficients must not vanish, e.g. g0019*p4 + g0020*p3
means that either p4 or p3 or both are non-vanishing.
{b12,a11 - 2*a33}
Relevance for the application:
The system of equations related to the Hamiltonian HAM:
2 2 2
HAM=u1 *a11 + u1*v2*b12 + u2 *a11 - u2*v1*b12 + u3 *a33
has apart from the Hamiltonian and Casimirs the following 3 first integrals:
1 2 2 1 2 2 1 2 2 1 2 2
FI=---*u1 *u3 *kap + ---*u1 *v1 + u1*u2*v1*v2 + ---*u2 *u3 *kap + ---*u2 *v2
2 2 2 2
1 2 2 1 2 2
+ ---*u3 *v1 + ---*u3 *v2
2 2
3 2 2 2
{HAM,FI} = - u1 *u3*v1*b12*kap - u1 *u2*u3*v2*b12*kap - u1 *u3 *v3*b12*kap
2 2 2
+ 2*u1 *u3*v1*v2*a11 - u1*u2 *u3*v1*b12*kap - 2*u1*u2*u3*v1 *a11
2 2 3
+ 2*u1*u2*u3*v2 *a11 + 2*u1*u3 *v2*v3*a11 + u1*u3*v1 *b12
2 3 2 2
+ u1*u3*v1*v2 *b12 - u2 *u3*v2*b12*kap - u2 *u3 *v3*b12*kap
2 2 2
- 2*u2 *u3*v1*v2*a11 - 2*u2*u3 *v1*v3*a11 + u2*u3*v1 *v2*b12
3 2 2 2 2
+ u2*u3*v2 *b12 + u3 *v1 *v3*b12 + u3 *v2 *v3*b12
2 2 2 2 2 2
FI=u1 *u3 *a11 + u1*u3 *v2*b12 + u2 *u3 *a11 - u2*u3 *v1*b12
{HAM,FI} = 0
4
FI=u3
{HAM,FI} = 0
And again in machine readable form:
HAM=u1**2*a11 + u1*v2*b12 + u2**2*a11 - u2*v1*b12 + u3**2*a33$
FI=1/2*u1**2*u3**2*kap + 1/2*u1**2*v1**2 + u1*u2*v1*v2 + 1/2*u2**2*u3**2*kap + 1
/2*u2**2*v2**2 + 1/2*u3**2*v1**2 + 1/2*u3**2*v2**2$
FI=u1**2*u3**2*a11 + u1*u3**2*v2*b12 + u2**2*u3**2*a11 - u2*u3**2*v1*b12$
FI=u3**4$