Solution 7 to problem over


Expressions | Parameters | Inequalities | Relevance | Back to problem over

Expressions

The solution is given through the following expressions:

r40=0


r41=0


r42=0


r43=0


r44=0


r45=0


r46=0


r47=0


r48=0


r49=0


r410=0


r411=0


r412=0


r413=0


r418=0


r421=0


r423=0


r424=0


r427=0


r429=0


r430=r460


r432=0


r433=0


r434=0


r435=0


r436=0


r437=0


r438=0


r439=0


r440=0


r441=0


r442=0


r443=0


r444=0


r447=0


r449=0


r450=0


r452=0


       - 4*a33*r460
r453=---------------
           b12


r454=0


r455=0


r456=0


r457=0


r458=0


r459=0


r462=0


r463=0


           2
      4*a33 *r460
r464=-------------
            2
         b12


r465=0


r466=0


       - 4*a33*r460
r467=---------------
           b12


r468=0


           2
      4*a33 *r460
r469=-------------
            2
         b12


r470=0


r471=0


r472=0


r473=0


r474=0


r475=0


r476=0


r477=0


r479=0


r482=0


r484=0


r485=0


r487=0


r488=0


r489=0


r490=0


r491=0


r492=0


r493=0


r494=0


r495=0


r497=0


r498=0


r499=0


r4100=0


r4101=0


r4102=0


r4103=0


r4104=0


r4105=0


r4106=0


r4108=0


r4109=0


r4110=r460


r4112=0


r4113=0


r4114=0


r4115=0


r4116=0


        - 4*a33*r460
r4117=---------------
            b12


r4118=0


            2
       4*a33 *r460
r4119=-------------
             2
          b12


r4120=0


r4121=0


r4122=0


r4123=0


r4124=0


r4125=0


a23=0


a22=2*a33


a13=0


        2    1     2
     a33  - ---*b12 *kap
             4
a11=---------------------
             a33


Parameters

Apart from the condition that they must not vanish to give a non-trivial solution and a non-singular solution with non-vanishing denominators, the following parameters are free:
 r460, a33, b12

Inequalities

In the following not identically vanishing expressions are shown. Any auxiliary variables g00?? are used to express that at least one of their coefficients must not vanish, e.g. g0019*p4 + g0020*p3 means that either p4 or p3 or both are non-vanishing.
 
                   2      2
{a33,b12,r460,4*a33  + b12 *kap}


Relevance for the application:

The system of equations related to the Hamiltonian HAM:

       2     2    1     2                            2    2
HAM=(u1 *(a33  - ---*b12 *kap) + u1*v2*a33*b12 + 2*u2 *a33  - u2*v1*a33*b12
                  4

          2    2
      + u3 *a33 )/a33

has apart from the Hamiltonian and Casimirs only the following first integral: 

       2   2    2       2                   2   2    2       4    2
FI=4*u1 *u2 *a33  - 4*u1 *u2*v1*a33*b12 + u1 *v1 *b12  + 4*u2 *a33

          3                  2   2    2     2   2    2          2
    - 4*u2 *v1*a33*b12 + 4*u2 *u3 *a33  + u2 *v1 *b12  - 4*u2*u3 *v1*a33*b12

        2   2    2
    + u3 *v1 *b12

                  2          2                    2        2             3    3
{HAM,FI} = 8*u1*u2 *u3*v1*a33 *b12 - 8*u1*u2*u3*v1 *a33*b12  + 2*u1*u3*v1 *b12

                  3          2           2   2       2
            + 8*u2 *u3*v2*a33 *b12 + 8*u2 *u3 *v3*a33 *b12

                  2                 2          2              2
            - 8*u2 *u3*v1*v2*a33*b12  - 8*u2*u3 *v1*v3*a33*b12

                        2       3       2   2       3
            + 2*u2*u3*v1 *v2*b12  + 2*u3 *v1 *v3*b12





And again in machine readable form:



HAM=(u1**2*(a33**2 - 1/4*b12**2*kap) + u1*v2*a33*b12 + 2*u2**2*a33**2 - u2*v1*
a33*b12 + u3**2*a33**2)/a33$

FI=4*u1**2*u2**2*a33**2 - 4*u1**2*u2*v1*a33*b12 + u1**2*v1**2*b12**2 + 4*u2**4*
a33**2 - 4*u2**3*v1*a33*b12 + 4*u2**2*u3**2*a33**2 + u2**2*v1**2*b12**2 - 4*u2*
u3**2*v1*a33*b12 + u3**2*v1**2*b12**2$