Solution 28 to problem e3c2new


Remaining equations | Expressions | Parameters | Relevance | Back to problem e3c2new

Equations

The following unsolved equations remain:
    2     2
0=m1  + m2


Expressions

The solution is given through the following expressions:

     1
a22=---*a33
     2


b22=0


b31=0


b32=0


b33=0


c12=0


c13=0


c22=0


c23=0


c33=0


     - m1*n2
n1=----------
       m2


n3=0


m3=0


r6=0


           2   2          2   2
    8*k1*m1 *n2  - 8*k1*m2 *n2
r5=-----------------------------
                 3
              a33 *m2


              3   2             2   2
     - 8*k1*m1 *n2  + 8*k1*m1*m2 *n2
r4=-----------------------------------
                   3   2
                a33 *m2


r3=0


               2   3           2   3
     - 24*k1*m1 *n2  - 24*k1*m2 *n2
r2=----------------------------------
                   3   2
                a33 *m2


               3   3              2   3
     - 24*k1*m1 *n2  - 24*k1*m1*m2 *n2
r1=-------------------------------------
                    3   3
                 a33 *m2


q20=0


q19=0


q17=0


q16=0


               2          2
      - 8*k1*m1  - 8*k1*m2
q15=------------------------
                 2
              a33


q14=0


q13=0


                2
      - 16*k1*m1 *n2
q12=-----------------
            2
         a33 *m2


     16*k1*m1*n2
q11=-------------
           2
        a33


               2          2
      - 8*k1*m1  - 8*k1*m2
q10=------------------------
                 2
              a33


q9=0


     - 16*k1*m1*n2
q8=----------------
            2
         a33


    16*k1*m2*n2
q7=-------------
          2
       a33


q5=0


q4=0


               2   2          2   2
     - 12*k1*m1 *n2  - 8*k1*m2 *n2
q3=---------------------------------
                  2   2
               a33 *m2


                 2
     - 8*k1*m1*n2
q2=----------------
          2
       a33 *m2


            2   2           2   2
    16*k1*m1 *n2  + 12*k1*m2 *n2
q1=-------------------------------
                 2   2
              a33 *m2


p56=0


p55=0


p54=0


p53=0


p52=0


p51=0


p50=0


p49=0


p48=0


p47=0


p46=0


p45=0


p44=0


p43=0


p42=0


p41=0


p40=0


p39=0


p38=0


p37=0


p36=0


p35=0


p34=0


p33=0


p32=0


p31=0


p30=0


p29=0


p28=0


p27=0


p26=0


p25=0


p24=0


      - 4*k1*m2
p23=------------
        a33


      - 8*k1*m1
p22=------------
        a33


     4*k1*m2
p21=---------
       a33


p20=0


p19=0


p18=0


p17=0


p16=0


p15=0


p14=0


     4*k1*m1
p13=---------
       a33


      - 8*k1*m2
p12=------------
        a33


      - 4*k1*m1
p11=------------
        a33


p10=0


p9=0


p8=0


p7=0


p6=0


p5=0


     - 4*k1*n2
p4=------------
       a33


    4*k1*m1*n2
p3=------------
      a33*m2


     - 4*k1*n2
p2=------------
       a33


    4*k1*m1*n2
p1=------------
      a33*m2


k125=0


k124=0


k122=0


k121=0


k120=0


k119=0


k118=0


k117=0


k116=0


k115=0


k114=0


k113=0


k112=0


k110=0


k109=0


k108=0


k107=0


k106=0


k105=0


k104=0


k103=0


k102=0


k101=0


k100=0


k99=0


k98=0


k97=0


k96=0


k95=0


k94=0


k93=0


k92=0


k91=0


k90=0


k89=0


k88=0


k87=0


k86=0


k85=0


k84=0


k83=0


k82=0


k81=0


k80=0


k79=0


k78=0


k77=0


k76=0


k75=0


k74=0


k73=0


k72=0


k71=0


k70=0


k69=0


k68=0


k67=0


k66=0


k65=0


k64=0


k63=0


k62=0


k61=0


k60=0


k59=0


k58=0


k57=0


k56=0


k55=0


k54=0


k53=0


k52=0


k51=0


k50=0


k49=0


k48=0


k47=0


k46=0


k45=0


k44=0


k43=0


k42=0


k41=0


k40=0


k38=0


k37=0


k36=0


k35=0


k34=0


k33=0


k32=0


k30=0


k29=0


k28=0


k27=0


k26=0


k25=0


k24=0


k23=0


k22=0


k21=0


k20=0


k19=0


k18=0


k17=0


k16=0


k14=0


k13=0


k12=0


k11=0


k10=0


k9=0


k8=0


k7=0


k6=0


k5=k1


k4=0


k3=2*k1


k2=0


Parameters

Apart from the condition that they must not vanish to give a non-trivial solution and a non-singular solution with non-vanishing denominators, the following parameters are free:
 k1,m1,m2,n2,a33

Relevance for the application:

The following expression INT is a first

integral for the Hamiltonian HAM:

              2            2              2                                 2
HAM=(a33*m2*u1  + a33*m2*u2  + 2*a33*m2*u3  + 2*m1*m2*v1 - 2*m1*n2*u1 + 2*m2 *v2

      + 2*m2*n2*u2)/(2*m2)

            3   3   4        3   3   2   2      3   3   4        2      3   2
INT=(k1*(a33 *m2 *u1  + 2*a33 *m2 *u1 *u2  + a33 *m2 *u2  - 4*a33 *m1*m2 *u1 *v1

                 2      3                 2      3   2           2      2      3
          - 8*a33 *m1*m2 *u1*u2*v2 + 4*a33 *m1*m2 *u2 *v1 + 4*a33 *m1*m2 *n2*u1

                 2      2         2        2   4   2           2   4
          + 4*a33 *m1*m2 *n2*u1*u2  + 4*a33 *m2 *u1 *v2 - 8*a33 *m2 *u1*u2*v1

                 2   4   2           2   3      2           2   3      3
          - 4*a33 *m2 *u2 *v2 - 4*a33 *m2 *n2*u1 *u2 - 4*a33 *m2 *n2*u2

                    2   3   2           2   3   2            2   2
          - 8*a33*m1 *m2 *v1  - 8*a33*m1 *m2 *v2  - 16*a33*m1 *m2 *n2*u2*v2

                     2      2   2            2      2   2
          + 16*a33*m1 *m2*n2 *u1  - 12*a33*m1 *m2*n2 *u2

                        3                        3
          + 16*a33*m1*m2 *n2*u1*v2 - 16*a33*m1*m2 *n2*u2*v1

                       2   2                 5   2           5   2
          - 8*a33*m1*m2 *n2 *u1*u2 - 8*a33*m2 *v1  - 8*a33*m2 *v2

                     4                     3   2   2           3   2   2
          + 16*a33*m2 *n2*u1*v1 + 12*a33*m2 *n2 *u1  - 8*a33*m2 *n2 *u2

                3      2           3   3          2   2   2
          - 8*m1 *m2*n2 *v1 - 24*m1 *n2 *u1 + 8*m1 *m2 *n2 *v2

                 2      3             3   2              2   3          4   2
          - 24*m1 *m2*n2 *u2 + 8*m1*m2 *n2 *v1 - 24*m1*m2 *n2 *u1 - 8*m2 *n2 *v2

                 3   3          3   3
          - 24*m2 *n2 *u2))/(a33 *m2 )



And again in machine readable form:



HAM=(a33*m2*u1**2 + a33*m2*u2**2 + 2*a33*m2*u3**2 + 2*m1*m2*v1 - 2*m1*n2*u1 + 2*
m2**2*v2 + 2*m2*n2*u2)/(2*m2)$

INT=(k1*(a33**3*m2**3*u1**4 + 2*a33**3*m2**3*u1**2*u2**2 + a33**3*m2**3*u2**4 - 
4*a33**2*m1*m2**3*u1**2*v1 - 8*a33**2*m1*m2**3*u1*u2*v2 + 4*a33**2*m1*m2**3*u2**
2*v1 + 4*a33**2*m1*m2**2*n2*u1**3 + 4*a33**2*m1*m2**2*n2*u1*u2**2 + 4*a33**2*m2
**4*u1**2*v2 - 8*a33**2*m2**4*u1*u2*v1 - 4*a33**2*m2**4*u2**2*v2 - 4*a33**2*m2**
3*n2*u1**2*u2 - 4*a33**2*m2**3*n2*u2**3 - 8*a33*m1**2*m2**3*v1**2 - 8*a33*m1**2*
m2**3*v2**2 - 16*a33*m1**2*m2**2*n2*u2*v2 + 16*a33*m1**2*m2*n2**2*u1**2 - 12*a33
*m1**2*m2*n2**2*u2**2 + 16*a33*m1*m2**3*n2*u1*v2 - 16*a33*m1*m2**3*n2*u2*v1 - 8*
a33*m1*m2**2*n2**2*u1*u2 - 8*a33*m2**5*v1**2 - 8*a33*m2**5*v2**2 + 16*a33*m2**4*
n2*u1*v1 + 12*a33*m2**3*n2**2*u1**2 - 8*a33*m2**3*n2**2*u2**2 - 8*m1**3*m2*n2**2
*v1 - 24*m1**3*n2**3*u1 + 8*m1**2*m2**2*n2**2*v2 - 24*m1**2*m2*n2**3*u2 + 8*m1*
m2**3*n2**2*v1 - 24*m1*m2**2*n2**3*u1 - 8*m2**4*n2**2*v2 - 24*m2**3*n2**3*u2))/(
a33**3*m2**3)$