Solution 51 to problem e3c2new


Expressions | Parameters | Relevance | Back to problem e3c2new

Expressions

The solution is given through the following expressions:

a22= - a33


b22=0


b31=0


b32=0


c12=0


c13=0


c22=0


c23=0


      1     2
     ---*b33
      4
c33=----------
       a33


n2=0


n3=0


m1=0


m2=0


m3=0


r6=0


r5=0


r4=0


r3=0


r2=0


r1=0


q20=0


q19=0


q17=0


q16=0


q15=0


q14=0


q13=0


q12=0


q11=0


q10=0


q9=0


q8=0


q7=0


q5=0


q4=0


q3=0


q2=0


q1=0


p56=0


p55=0


         1
      - ---*b33*k26*n1
         4
p54=-------------------
              2
           a33


p53=0


p52=0


         1
      - ---*k26*n1
         2
p51=---------------
          a33


p50=0


p49=0


p48=0


p47=0


p46=0


p45=0


         1
      - ---*b33*k23*n1
         4
p44=-------------------
              2
           a33


p43=0


p42=0


p41=0


p40=0


      1
     ---*k23*n1
      2
p39=------------
        a33


p38=0


p37=0


p36=0


p35=0


         1
      - ---*b33*k26*n1
         4
p34=-------------------
              2
           a33


p33=0


p32=0


         1
      - ---*k26*n1
         2
p31=---------------
          a33


p30=0


p29=0


         1
      - ---*b33*k23*n1
         4
p28=-------------------
              2
           a33


p27=0


p26=0


p25=0


p24=0


p23=0


      1
     ---*k23*n1
      2
p22=------------
        a33


p21=0


         1
      - ---*b33*k26*n1
         4
p20=-------------------
              2
           a33


p19=0


p18=0


         1                1
      - ---*a33*k26*n1 - ---*b33*k23*n1
         2                4
p17=------------------------------------
                       2
                    a33


p16=0


p15=0


p14=0


p13=0


p12=0


      1
     ---*k23*n1
      2
p11=------------
        a33


p10=0


p9=0


p8=0


p7=0


p6=0


p5=0


p4=0


p3=0


p2=0


p1=0


k125=0


k124=0


k122=0


k121=0


       1     2
      ---*b33 *k26
       4
k120=--------------
             2
          a33


k119=0


k118=0


      b33*k26
k117=---------
        a33


k116=0


       1     2
      ---*b33 *k26
       4
k115=--------------
             2
          a33


k114=0


k113=0


      b33*k26
k112=---------
        a33


k110=0


k109=0


k108=k26


k107=0


k106=k26


k105=0


k104=0


k103=0


k102=0


k101=0


k100=0


k99=0


k98=0


k97=0


k96=0


k95=0


k94=0


k93=0


k92=0


k91=0


k90=0


k89=0


k88=0


k87=0


k86=0


k85=0


k84=0


k83=0


k82=0


k81=0


k80=k23


k79=0


k78=0


k77=0


k76=0


k75=0


k74=0


k73=0


k72=0


k71=0


      1     2
     ---*b33 *k26
      4
k70=--------------
            2
         a33


k69=0


k68=0


     b33*k26
k67=---------
       a33


k66=0


      1     2
     ---*b33 *k26
      2
k65=--------------
            2
         a33


k64=0


k63=0


     b33*k26
k62=---------
       a33


k61=0


k60=0


k59=0


k58=k26


k57=0


k56=k26


k55=0


k54=0


     b33*k26
k53=---------
       a33


k52=0


k51=0


k50=0


k49=0


k48=0


k47=0


k46=0


k45=0


k44=k23


k43=0


k42=0


k41=0


k40=0


k38=0


k37=0


k36=0


      1     2
     ---*b33 *k26
      4
k35=--------------
            2
         a33


k34=0


k33=0


     b33*k26
k32=---------
       a33


k30=0


k29=0


k28=k26


k27=0


k25=0


k24=0


k22=0


k21=0


k20=0


k19=0


k18=0


k17=0


k16=0


k14=0


k13=0


k12=0


k11=0


k10=0


k9=0


k8=0


k7=0


k6=0


k5=0


k4=0


k3=0


k2=0


k1=0


Parameters

Apart from the condition that they must not vanish to give a non-trivial solution and a non-singular solution with non-vanishing denominators, the following parameters are free:
 b33,k26,k23,n1,a33

Relevance for the application:

The following expression INT is a first

integral for the Hamiltonian HAM:

             2   2        2   2        2   2
HAM=( - 4*a33 *u1  - 4*a33 *u2  + 4*a33 *u3  + 4*a33*b33*u3*v3 + 4*a33*n1*u1

           2   2
      + b33 *v3 )/(4*a33)

          2          2           2          2           2       3
INT=(4*a33 *k23*u1*u3 *v1 + 4*a33 *k23*u2*u3 *v2 + 4*a33 *k23*u3 *v3

             2       2   2        2       2   2        2       2   2
      + 4*a33 *k26*u1 *v1  + 4*a33 *k26*u1 *v2  + 4*a33 *k26*u1 *v3

             2       2   2        2       2   2        2       2   2
      + 4*a33 *k26*u2 *v1  + 4*a33 *k26*u2 *v2  + 4*a33 *k26*u2 *v3

                           3                         2                         2
      + 4*a33*b33*k26*u1*v1  + 4*a33*b33*k26*u1*v1*v2  + 4*a33*b33*k26*u1*v1*v3

                           2                         3                         2
      + 4*a33*b33*k26*u2*v1 *v2 + 4*a33*b33*k26*u2*v2  + 4*a33*b33*k26*u2*v2*v3

                       2
      + 2*a33*k23*n1*u1 *v1 + 2*a33*k23*n1*u1*u2*v2 + 2*a33*k23*n1*u1*u3*v3

                          2                     2                     2
      - 2*a33*k26*n1*u1*v1  - 2*a33*k26*n1*u1*v2  - 2*a33*k26*n1*u1*v3

           2       4        2       2   2      2       2   2      2       4
      + b33 *k26*v1  + 2*b33 *k26*v1 *v2  + b33 *k26*v1 *v3  + b33 *k26*v2

           2       2   2                   2
      + b33 *k26*v2 *v3  - b33*k23*n1*u1*v1  - b33*k23*n1*u2*v1*v2

                                           3                   2
      - b33*k23*n1*u3*v1*v3 - b33*k26*n1*v1  - b33*k26*n1*v1*v2

                        2        2
      - b33*k26*n1*v1*v3 )/(4*a33 )



And again in machine readable form:



HAM=( - 4*a33**2*u1**2 - 4*a33**2*u2**2 + 4*a33**2*u3**2 + 4*a33*b33*u3*v3 + 4*
a33*n1*u1 + b33**2*v3**2)/(4*a33)$

INT=(4*a33**2*k23*u1*u3**2*v1 + 4*a33**2*k23*u2*u3**2*v2 + 4*a33**2*k23*u3**3*v3
 + 4*a33**2*k26*u1**2*v1**2 + 4*a33**2*k26*u1**2*v2**2 + 4*a33**2*k26*u1**2*v3**
2 + 4*a33**2*k26*u2**2*v1**2 + 4*a33**2*k26*u2**2*v2**2 + 4*a33**2*k26*u2**2*v3
**2 + 4*a33*b33*k26*u1*v1**3 + 4*a33*b33*k26*u1*v1*v2**2 + 4*a33*b33*k26*u1*v1*
v3**2 + 4*a33*b33*k26*u2*v1**2*v2 + 4*a33*b33*k26*u2*v2**3 + 4*a33*b33*k26*u2*v2
*v3**2 + 2*a33*k23*n1*u1**2*v1 + 2*a33*k23*n1*u1*u2*v2 + 2*a33*k23*n1*u1*u3*v3 -
 2*a33*k26*n1*u1*v1**2 - 2*a33*k26*n1*u1*v2**2 - 2*a33*k26*n1*u1*v3**2 + b33**2*
k26*v1**4 + 2*b33**2*k26*v1**2*v2**2 + b33**2*k26*v1**2*v3**2 + b33**2*k26*v2**4
 + b33**2*k26*v2**2*v3**2 - b33*k23*n1*u1*v1**2 - b33*k23*n1*u2*v1*v2 - b33*k23*
n1*u3*v1*v3 - b33*k26*n1*v1**3 - b33*k26*n1*v1*v2**2 - b33*k26*n1*v1*v3**2)/(4*
a33**2)$