Solution 37 to problem e3null


Expressions | Parameters | Relevance | Back to problem e3null

Expressions

The solution is given through the following expressions:

     1
a22=---*a33
     2


b22=0


b31=0


b33=0


c12=0


c13=0


c22=0


c23=0


         1     2
      - ---*b32
         2
c33=-------------
         a33


n1=0


n2=0


    a33*m2
n3=--------
     b32


m1=0


m3=0


r6=0


r5=0


r4=0


r3=0


r2=0


r1=0


q19=0


q18=0


q17=0


            2
     8*k1*m2
q16=----------
     a33*b32


q15=0


            2
     4*k1*m2
q14=----------
          2
       a33


q13=0


q12=0


q11=0


q10=0


           2
    4*k1*m2
q9=----------
         2
      a33


q8=0


q7=0


q5=0


q4=0


              2
     - 4*k1*m2
q3=-------------
          2
       b32


q2=0


              2
     - 4*k1*m2
q1=-------------
          2
       b32


p50=0


             2
      - 4*b32 *k1*m2
p49=-----------------
             3
          a33


p48=0


      - 12*b32*k1*m2
p47=-----------------
             2
          a33


p46=0


p45=0


p44=0


p43=0


p42=0


p41=0


p40=0


p39=0


p38=0


p37=0


p36=0


     16*k1*m2
p35=----------
       a33


p34=0


p33=0


p32=0


p31=0


p30=0


p29=0


p28=0


p27=0


p26=0


p25=0


p24=0


p23=0


p22=0


p21=0


p20=0


     4*k1*m2
p19=---------
       a33


p18=0


     4*k1*m2
p17=---------
       a33


p16=0


p15=0


p14=0


p13=0


p12=0


p11=0


p10=0


p9=0


p8=0


     - 4*k1*m2
p7=------------
       b32


p6=0


     - 4*k1*m2
p5=------------
       b32


p4=0


p3=0


p2=0


p1=0


k104=0


k103=0


k102=0


k101=0


k100=0


             4
      - 2*b32 *k1
k99=--------------
            4
         a33


k98=0


             3
      - 4*b32 *k1
k97=--------------
            3
         a33


k96=0


k95=0


             4
      - 2*b32 *k1
k94=--------------
            4
         a33


k93=0


k92=0


             2
      - 8*b32 *k1
k91=--------------
            2
         a33


k90=0


k89=0


             2
      - 2*b32 *k1
k88=--------------
            2
         a33


k87=0


             2
      - 2*b32 *k1
k86=--------------
            2
         a33


k85=0


k84=0


k83=0


k82=0


k81=0


k80=0


k79=0


k78=0


k77=0


k76=0


k75=0


k74=0


k73=0


k72=0


k71=0


k70=0


k69=0


k68=0


k67=0


k66=0


k65=0


     8*b32*k1
k64=----------
       a33


k63=0


k62=0


k61=0


k60=0


k59=0


k58=0


k57=0


k56=0


           4
      - b32 *k1
k55=------------
           4
        a33


k54=0


k53=0


k52=0


k51=0


             4
      - 2*b32 *k1
k50=--------------
            4
         a33


k49=0


k48=0


k47=0


k46=0


k45=0


k44=0


k43=0


k42=0


k41=0


k40=0


k39=0


k38=0


k37=0


k36=0


k35=0


k34=0


k33=0


     4*b32*k1
k32=----------
       a33


k31=0


     4*b32*k1
k30=----------
       a33


k29=0


k28=0


k27=0


k26=0


           4
      - b32 *k1
k25=------------
           4
        a33


k24=0


k23=0


k21=0


k20=0


k19=0


k18=0


k17=0


k16=0


k14=0


k13=0


k12=0


k11=0


k10=0


k9=0


k8=0


k7=0


k6=0


k5=k1


k4=0


k3=2*k1


k2=0


Parameters

Apart from the condition that they must not vanish to give a non-trivial solution and a non-singular solution with non-vanishing denominators, the following parameters are free:
 k1,b32,m2,a33

Relevance for the application:

The following expression INT is a first

integral for the Hamiltonian HAM:

        2       2      2       2        2       2        2
HAM=(a33 *b32*u1  + a33 *b32*u2  + 2*a33 *b32*u3  + 2*a33 *m2*u3

                 2                              3   2
      + 2*a33*b32 *u3*v2 + 2*a33*b32*m2*v2 - b32 *v3 )/(2*a33*b32)

            4    2   4        4    2   2   2      4    2   4
INT=(k1*(a33 *b32 *u1  + 2*a33 *b32 *u1 *u2  + a33 *b32 *u2

                 4          2           4          2           4   2   2
          - 4*a33 *b32*m2*u1 *u3 - 4*a33 *b32*m2*u2 *u3 - 4*a33 *m2 *u1

                 4   2   2        3    3   2              3    3   2
          - 4*a33 *m2 *u2  + 4*a33 *b32 *u1 *u3*v2 + 4*a33 *b32 *u2 *u3*v2

                 3    3      2           3    2      2
          + 8*a33 *b32 *u2*u3 *v3 + 4*a33 *b32 *m2*u1 *v2

                 3    2      2            3    2
          + 4*a33 *b32 *m2*u2 *v2 + 16*a33 *b32 *m2*u2*u3*v3

                 3       2              2    4   2   2        2    4   2   2
          + 8*a33 *b32*m2 *u2*v3 - 2*a33 *b32 *u1 *v3  - 2*a33 *b32 *u2 *v3

                 2    4   2   2         2    3         2        2    2   2   2
          - 8*a33 *b32 *u3 *v3  - 12*a33 *b32 *m2*u3*v3  + 4*a33 *b32 *m2 *v1

                 2    2   2   2            5         2            4         2
          + 4*a33 *b32 *m2 *v2  - 4*a33*b32 *u3*v2*v3  - 4*a33*b32 *m2*v2*v3

               6   4        6   2   2        6   2   2      6   4
          - b32 *v1  - 2*b32 *v1 *v2  - 2*b32 *v1 *v3  - b32 *v2

                 6   2   2       4    2
          - 2*b32 *v2 *v3 ))/(a33 *b32 )



And again in machine readable form:



HAM=(a33**2*b32*u1**2 + a33**2*b32*u2**2 + 2*a33**2*b32*u3**2 + 2*a33**2*m2*u3 +
 2*a33*b32**2*u3*v2 + 2*a33*b32*m2*v2 - b32**3*v3**2)/(2*a33*b32)$

INT=(k1*(a33**4*b32**2*u1**4 + 2*a33**4*b32**2*u1**2*u2**2 + a33**4*b32**2*u2**4
 - 4*a33**4*b32*m2*u1**2*u3 - 4*a33**4*b32*m2*u2**2*u3 - 4*a33**4*m2**2*u1**2 - 
4*a33**4*m2**2*u2**2 + 4*a33**3*b32**3*u1**2*u3*v2 + 4*a33**3*b32**3*u2**2*u3*v2
 + 8*a33**3*b32**3*u2*u3**2*v3 + 4*a33**3*b32**2*m2*u1**2*v2 + 4*a33**3*b32**2*
m2*u2**2*v2 + 16*a33**3*b32**2*m2*u2*u3*v3 + 8*a33**3*b32*m2**2*u2*v3 - 2*a33**2
*b32**4*u1**2*v3**2 - 2*a33**2*b32**4*u2**2*v3**2 - 8*a33**2*b32**4*u3**2*v3**2 
- 12*a33**2*b32**3*m2*u3*v3**2 + 4*a33**2*b32**2*m2**2*v1**2 + 4*a33**2*b32**2*
m2**2*v2**2 - 4*a33*b32**5*u3*v2*v3**2 - 4*a33*b32**4*m2*v2*v3**2 - b32**6*v1**4
 - 2*b32**6*v1**2*v2**2 - 2*b32**6*v1**2*v3**2 - b32**6*v2**4 - 2*b32**6*v2**2*
v3**2))/(a33**4*b32**2)$