Solution 51 to problem e3quant


Remaining equations | Expressions | Parameters | Relevance | Back to problem e3quant

Equations

The following unsolved equations remain:
    2     2
0=m1  + m2


Expressions

The solution is given through the following expressions:

     1
a22=---*a33
     2


b22=0


b31=0


b32=0


b33=0


c12=0


c13=0


c22=0


c23=0


c33=0


     - m1*n2
n1=----------
       m2


n3=0


m3=0


     - 16*k1*m1*n2
r6=----------------
            2
         a33


            2                    2
     - 3*a33 *k1*m2 - 16*k1*m2*n2
r5=--------------------------------
                    3
                 a33


            2                    2
     - 3*a33 *k1*m1 + 16*k1*m1*n2
r4=--------------------------------
                    3
                 a33


              2
    4*k1*m1*n2
r3=-------------
         2
      a33 *m2


    k1*n2
r2=-------
     a33


    3*k1*m1*n2
r1=------------
      a33*m2


q20=0


            2          2
     4*k1*m1  + 4*k1*m2
q19=---------------------
               2
            a33


q18=0


q17=0


            2          2
     4*k1*m1  + 4*k1*m2
q16=---------------------
               2
            a33


     4*k1*m1
q14=---------
       a33


     4*k1*m2
q13=---------
       a33


     8*k1*m1
q11=---------
       a33


                2
      - 16*k1*m1 *n2
q10=-----------------
            2
         a33 *m2


     - 16*k1*m1*n2
q9=----------------
            2
         a33


     - 4*k1*m1*n2
q8=---------------
       a33*m2


        7     2             2
     - ---*a33 *k1 + 4*k1*n2
        2
q7=---------------------------
                 2
              a33


     - 8*k1*m2
q6=------------
       a33


    16*k1*m1*n2
q5=-------------
          2
       a33


    16*k1*m2*n2
q4=-------------
          2
       a33


    4*k1*n2
q3=---------
      a33


                 2
     - 8*k1*m1*n2
q2=----------------
          2
       a33 *m2


     1     2             2
    ---*a33 *k1 - 4*k1*n2
     2
q1=------------------------
                2
             a33


p56=0


p55=0


p54=0


p53=0


p52=0


p51=0


p50=0


p49=0


p48=0


p47=0


p46=0


p45=0


p44=0


p43=0


p42=0


p41=0


p40=0


p39=0


p38=0


p37=0


p36=0


p35=0


p34=0


p33=0


p32=0


p31=0


p30=0


p29=0


p28=0


p27=0


p26=0


      - 4*k1*m2
p25=------------
        a33


     4*k1*m1
p24=---------
       a33


p23=0


      - 4*k1*n2
p22=------------
        a33


p21=0


p20=0


p19=0


p18=0


p17=0


p16=0


p15=0


p14=0


p13=0


p12=0


p11=0


      - 8*k1*m1
p10=------------
        a33


     - 8*k1*m2
p9=------------
       a33


p8= - 4*k1


    4*k1*m1*n2
p7=------------
      a33*m2


p6=0


    4*k1*m2
p5=---------
      a33


     - 4*k1*m1
p4=------------
       a33


p3=0


     - 4*k1*n2
p2=------------
       a33


    4*k1*m1*n2
p1=------------
      a33*m2


k125=0


k124=0


k123=0


k122=0


k121=0


k120=0


k119=0


k118=0


k117=0


k116=0


k115=0


k114=0


k113=0


k112=0


k110=0


k109=0


k108=0


k107=0


k106=0


k105=0


k104=0


k103=0


k102=0


k100=0


k99=0


k98=0


k97=0


k95=0


k94=0


k93=0


k91=0


k90=0


k89=0


k88=0


k87=0


k86=0


k85=0


k84=0


k83=0


k82=0


k81=0


k80=0


k79=0


k78=0


k77=0


k76=0


k75=0


k74=0


k73=0


k72=0


k71=0


k70=0


k69=0


k68=0


k67=0


k66=0


k65=0


k64=0


k63=0


k62=0


k61=0


k59=0


k58=0


k57=k1


k56=0


k55=0


k54=0


k53=0


k52=0


k51=0


k50=0


k49=0


k48=0


k47=0


k46=0


k45=0


k44=0


k43=0


k42=0


k41=0


k40=0


k39=0


k38=0


k37=0


k36=0


k35=0


k34=0


k33=0


k32=0


k31=0


k30=0


k29=0


k28=0


k27=0


k26=0


k25=0


k24=0


k23=0


k22=0


k21=0


k20=0


k19=0


k18=0


k17=0


k16=0


k15=0


k14=0


k13=0


k12=0


k11=0


k10=0


k9=0


k8=0


k7=2*k1


k6=0


k5=0


k4=0


k3=0


k2=0


Parameters

Apart from the condition that they must not vanish to give a non-trivial solution and a non-singular solution with non-vanishing denominators, the following parameters are free:
 k1,m2,m1,n2,a33

Relevance for the application:

The following expression INT is a first

integral for the Hamiltonian HAM:

              2            2              2                                 2
HAM=(a33*m2*u1  + a33*m2*u2  + 2*a33*m2*u3  + 2*m1*m2*v1 - 2*m1*n2*u1 + 2*m2 *v2

      + 2*m2*n2*u2)/(2*m2)

              3      4        3      2            3      2        3            2
INT=(k1*(2*a33 *m2*u1  + 4*a33 *m2*u1 *u2*u3 + a33 *m2*u1  + 2*a33 *m2*u1*u2*v2

                 3         2        3                 2
          - 8*a33 *m2*u1*u3  - 7*a33 *m2*u1*v1 + 8*a33 *m1*m2*u1*u3*v2

                  2                    2         3         2         3
          + 16*a33 *m1*m2*u1*v2 - 8*a33 *m1*m2*u2  - 16*a33 *m1*m2*u3

                 2                    2                 2         3
          + 8*a33 *m1*m2*v1*v2 - 6*a33 *m1*m2*v1 + 8*a33 *m1*n2*u1

                 2                 2         2           2
          + 6*a33 *m1*n2*u1 + 8*a33 *m1*n2*u2 *u3 - 8*a33 *m1*n2*u2*v1

                 2   2   2            2   2      2        2   2
          + 8*a33 *m2 *u1 *u3 - 16*a33 *m2 *u2*u3  - 8*a33 *m2 *u2*u3*v2

                  2   2   2        2   2              2   2
          - 16*a33 *m2 *u3  + 8*a33 *m2 *u3*v2 - 6*a33 *m2 *v2

                 2         2           2                       2         2
          - 8*a33 *m2*n2*u1 *u2 - 8*a33 *m2*n2*u1*u2*v2 + 8*a33 *m2*n2*u2

                 2                    2                    2
          + 2*a33 *m2*n2*u2 + 8*a33*m1 *m2*u1*v3 + 8*a33*m1 *m2*v1*v3

                     2      2
          - 32*a33*m1 *n2*v1  + 32*a33*m1*m2*n2*u2*u3 - 32*a33*m1*m2*n2*u3*v1

                                             2                    2
          - 32*a33*m1*m2*n2*v3 - 16*a33*m1*n2 *u1*u2 + 8*a33*m1*n2 *u3

                    3                 3                  2
          + 8*a33*m2 *u1*v3 + 8*a33*m2 *v1*v3 + 32*a33*m2 *n2*u1*u3

                       2   2              2                    2
          - 8*a33*m2*n2 *u1  + 8*a33*m2*n2 *u1*v1 + 32*m1*m2*n2 *v1

                 2   2            3
          - 32*m2 *n2 *v2))/(2*a33 *m2)



And again in machine readable form:



HAM=(a33*m2*u1**2 + a33*m2*u2**2 + 2*a33*m2*u3**2 + 2*m1*m2*v1 - 2*m1*n2*u1 + 2*
m2**2*v2 + 2*m2*n2*u2)/(2*m2)$

INT=(k1*(2*a33**3*m2*u1**4 + 4*a33**3*m2*u1**2*u2*u3 + a33**3*m2*u1**2 + 2*a33**
3*m2*u1*u2*v2**2 - 8*a33**3*m2*u1*u3**2 - 7*a33**3*m2*u1*v1 + 8*a33**2*m1*m2*u1*
u3*v2 + 16*a33**2*m1*m2*u1*v2 - 8*a33**2*m1*m2*u2**3 - 16*a33**2*m1*m2*u3**3 + 8
*a33**2*m1*m2*v1*v2 - 6*a33**2*m1*m2*v1 + 8*a33**2*m1*n2*u1**3 + 6*a33**2*m1*n2*
u1 + 8*a33**2*m1*n2*u2**2*u3 - 8*a33**2*m1*n2*u2*v1 + 8*a33**2*m2**2*u1**2*u3 - 
16*a33**2*m2**2*u2*u3**2 - 8*a33**2*m2**2*u2*u3*v2 - 16*a33**2*m2**2*u3**2 + 8*
a33**2*m2**2*u3*v2 - 6*a33**2*m2**2*v2 - 8*a33**2*m2*n2*u1**2*u2 - 8*a33**2*m2*
n2*u1*u2*v2 + 8*a33**2*m2*n2*u2**2 + 2*a33**2*m2*n2*u2 + 8*a33*m1**2*m2*u1*v3 + 
8*a33*m1**2*m2*v1*v3 - 32*a33*m1**2*n2*v1**2 + 32*a33*m1*m2*n2*u2*u3 - 32*a33*m1
*m2*n2*u3*v1 - 32*a33*m1*m2*n2*v3 - 16*a33*m1*n2**2*u1*u2 + 8*a33*m1*n2**2*u3 + 
8*a33*m2**3*u1*v3 + 8*a33*m2**3*v1*v3 + 32*a33*m2**2*n2*u1*u3 - 8*a33*m2*n2**2*
u1**2 + 8*a33*m2*n2**2*u1*v1 + 32*m1*m2*n2**2*v1 - 32*m2**2*n2**2*v2))/(2*a33**3
*m2)$