Solution 7 to problem e3quant
Expressions |
Parameters |
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Back to problem e3quant
Expressions
The solution is given through the following expressions:
1
a22=---*a33
2
b22=0
b31=0
b32=0
b33=0
c12=0
c13=0
c22=0
c23=0
c33=0
n1=0
n2=0
m1=0
m3=0
r6=0
- 3*k1*m2
r5=------------
a33
- 4*k1*m2*n3
r4=---------------
2
a33
- k1*n3
r3=----------
a33
r2=0
r1=0
q20=0
2
4*k1*m2
q19=----------
2
a33
q18=0
q17=0
2
4*k1*m2
q16=----------
2
a33
q14=0
4*k1*m2
q13=---------
a33
8*k1*m2*n3
q11=------------
2
a33
q10=0
q9=0
q8=0
7 2 2
- ---*a33 *k1 - 4*k1*n3
2
q7=---------------------------
2
a33
- 8*k1*m2
q6=------------
a33
q5=0
q4=0
q3=0
q2=0
1 2 2
---*a33 *k1 - 4*k1*n3
2
q1=------------------------
2
a33
p56=0
p55=0
p54=0
p53=0
p52=0
p51=0
p50=0
p49=0
p48=0
p47=0
p46=0
p45=0
p44=0
p43=0
p42=0
p41=0
p40=0
p39=0
p38=0
p37=0
p36=0
p35=0
p34=0
p33=0
p32=0
p31=0
p30=0
p29=0
p28=0
p27=0
p26=0
- 4*k1*m2
p25=------------
a33
p24=0
- 4*k1*n3
p23=------------
a33
p22=0
p21=0
p20=0
p19=0
p18=0
p17=0
p16=0
p15=0
p14=0
p13=0
p12=0
p11=0
p10=0
- 8*k1*m2
p9=------------
a33
p8= - 4*k1
p7=0
p6=0
4*k1*m2
p5=---------
a33
p4=0
- 4*k1*n3
p3=------------
a33
p2=0
p1=0
k125=0
k124=0
k123=0
k122=0
k121=0
k120=0
k119=0
k118=0
k117=0
k116=0
k115=0
k114=0
k113=0
k112=0
k110=0
k109=0
k108=0
k107=0
k106=0
k105=0
k104=0
k103=0
k102=0
k100=0
k99=0
k98=0
k97=0
k95=0
k94=0
k93=0
k91=0
k90=0
k89=0
k88=0
k87=0
k86=0
k85=0
k84=0
k83=0
k82=0
k81=0
k80=0
k79=0
k78=0
k77=0
k76=0
k75=0
k74=0
k73=0
k72=0
k71=0
k70=0
k69=0
k68=0
k67=0
k66=0
k65=0
k64=0
k63=0
k62=0
k61=0
k59=0
k58=0
k57=k1
k56=0
k55=0
k54=0
k53=0
k52=0
k51=0
k50=0
k49=0
k48=0
k47=0
k46=0
k45=0
k44=0
k43=0
k42=0
k41=0
k40=0
k39=0
k38=0
k37=0
k36=0
k35=0
k34=0
k33=0
k32=0
k31=0
k30=0
k29=0
k28=0
k27=0
k26=0
k25=0
k24=0
k23=0
k22=0
k21=0
k20=0
k19=0
k18=0
k17=0
k16=0
k15=0
k14=0
k13=0
k12=0
k11=0
k10=0
k9=0
k8=0
k7=2*k1
k6=0
k5=0
k4=0
k3=0
k2=0
Parameters
Apart from the condition that they must not vanish to give
a non-trivial solution and a non-singular solution with
non-vanishing denominators, the following parameters are free:
n3,m2,k1,a33
Relevance for the application:
The following expression INT is a first
integral for the Hamiltonian HAM:
2 2 2
a33*u1 + a33*u2 + 2*a33*u3 + 2*m2*v2 + 2*n3*u3
HAM=---------------------------------------------------
2
2 4 2 2 2 2 2 2
INT=(k1*(2*a33 *u1 + 4*a33 *u1 *u2*u3 + a33 *u1 + 2*a33 *u1*u2*v2
2 2 2 2 2
- 8*a33 *u1*u3 - 7*a33 *u1*v1 + 8*a33*m2*u1 *u3 - 16*a33*m2*u2*u3
2
- 8*a33*m2*u2*u3*v2 - 16*a33*m2*u3 + 8*a33*m2*u3*v2 - 6*a33*m2*v2
2 2 2
- 8*a33*n3*u1*u2 - 8*a33*n3*u2 *v2 - 2*a33*n3*u3 + 8*m2 *u1*v3
2 2 2 2
+ 8*m2 *v1*v3 + 16*m2*n3*u1*v2 - 8*m2*n3*v1 - 8*n3 *u1 - 8*n3 *u1*v1)
2
)/(2*a33 )
And again in machine readable form:
HAM=(a33*u1**2 + a33*u2**2 + 2*a33*u3**2 + 2*m2*v2 + 2*n3*u3)/2$
INT=(k1*(2*a33**2*u1**4 + 4*a33**2*u1**2*u2*u3 + a33**2*u1**2 + 2*a33**2*u1*u2*
v2**2 - 8*a33**2*u1*u3**2 - 7*a33**2*u1*v1 + 8*a33*m2*u1**2*u3 - 16*a33*m2*u2*u3
**2 - 8*a33*m2*u2*u3*v2 - 16*a33*m2*u3**2 + 8*a33*m2*u3*v2 - 6*a33*m2*v2 - 8*a33
*n3*u1*u2**2 - 8*a33*n3*u2**2*v2 - 2*a33*n3*u3 + 8*m2**2*u1*v3 + 8*m2**2*v1*v3 +
16*m2*n3*u1*v2 - 8*m2*n3*v1 - 8*n3**2*u1**2 - 8*n3**2*u1*v1))/(2*a33**2)$