Solution 2 to problem N1t13s14f2


Expressions | Parameters | Inequalities | Relevance | Back to problem N1t13s14f2

Expressions

The solution is given through the following expressions:

q14=0


q11=0


q10=0


q9=0


q8=0


q7=0


q6=0


q5=0


q4=0


q3=0


q2=0


q1=0


p11=0


p10=0


p9=0


p8=0


p7=0


p5=0


p4=0


p3=0


p2=0


p1=0


Parameters

Apart from the condition that they must not vanish to give a non-trivial solution and a non-singular solution with non-vanishing denominators, the following parameters are free:
 q13, q12, p6

Inequalities

In the following not identically vanishing expressions are shown. Any auxiliary variables g00?? are used to express that at least one of their coefficients must not vanish, e.g. g0019*p4 + g0020*p3 means that either p4 or p3 or both are non-vanishing.
 
{p6,g0006*q13 + g0007*q12}


Relevance for the application:



The equation: 


f =Df*f  *f *f*p6
 t     2x  x
The symmetry:
f =f  *f *f*q12 + f  *f  *f*q13
 s  4x  x          3x  2x
And now in machine readable form:

The system:

df(f(1),t)=d(1,f(1))*df(f(1),x,2)*df(f(1),x)*f(1)*p6$
The symmetry:
df(f(1),s)=df(f(1),x,4)*df(f(1),x)*f(1)*q12 + df(f(1),x,3)*df(f(1),x,2)*f(1)*q13
$