Solution 1 to problem N1t2s6b1
Expressions |
Parameters |
Inequalities |
Relevance |
Back to problem N1t2s6b1
Expressions
The solution is given through the following expressions:
p1=0
Parameters
Apart from the condition that they must not vanish to give
a non-trivial solution and a non-singular solution with
non-vanishing denominators, the following parameters are free:
q6, q5, q4, q3, q2, q1, p2
Inequalities
In the following not identically vanishing expressions are shown.
Any auxiliary variables g00?? are used to express that at least
one of their coefficients must not vanish, e.g. g0019*p4 + g0020*p3
means that either p4 or p3 or both are non-vanishing.
{q1,p2}
Relevance for the application:
The equation:
b =b *p2
t x
The symmetry:
7 2 2 4
b =b *q5 + Db *Db*b*q1 + b *q6 + b *b *q2 + b *b*q3 + b *b *q4
s x 3x 2x x x
And now in machine readable form:
The system:
df(b(1),t)=df(b(1),x)*p2$
The symmetry:
df(b(1),s)=b(1)**7*q5 + d(1,df(b(1),x))*d(1,b(1))*b(1)*q1 + df(b(1),x,3)*q6 + df
(b(1),x,2)*b(1)**2*q2 + df(b(1),x)**2*b(1)*q3 + df(b(1),x)*b(1)**4*q4$