Solution 1 to problem N1t2s4f1
Expressions |
Parameters |
Inequalities |
Relevance |
Back to problem N1t2s4f1
Expressions
The solution is given through the following expressions:
p1=0
Parameters
Apart from the condition that they must not vanish to give
a non-trivial solution and a non-singular solution with
non-vanishing denominators, the following parameters are free:
q4, q3, q2, q1, p2
Inequalities
In the following not identically vanishing expressions are shown.
Any auxiliary variables g00?? are used to express that at least
one of their coefficients must not vanish, e.g. g0019*p4 + g0020*p3
means that either p4 or p3 or both are non-vanishing.
{g0009*q4 + g0010*q3 + g0011*q2 + g0012*q1,g0005*q3 + g0006*q2 + g0007*q1,p2}
Relevance for the application:
The equation:
f =f *p2
t x
The symmetry:
2
f =Df *f*q1 + (Df) *f*q2 + Df*f *q3 + f *q4
s x x 2x
And now in machine readable form:
The system:
df(f(1),t)=df(f(1),x)*p2$
The symmetry:
df(f(1),s)=d(1,df(f(1),x))*f(1)*q1 + d(1,f(1))**2*f(1)*q2 + d(1,f(1))*df(f(1),x)
*q3 + df(f(1),x,2)*q4$