Solution 1 to problem N1t4s12f1
Expressions |
Parameters |
Inequalities |
Relevance |
Back to problem N1t4s12f1
Expressions
The solution is given through the following expressions:
q35=0
q34=0
q33=0
q32=0
q31=0
q30=0
q29=0
q28=0
q27=0
q26=0
q25=0
q24=0
q23=0
q22=0
q21=0
q20=0
q19=0
q18=0
q17=0
q16=0
q15=0
q14=0
q13=0
q11=0
q10=0
q8=0
q7=0
q6=0
q5=0
q4=0
q3=0
q2=0
q1=0
p4=0
p2=0
5*p1*q12
q9=----------
p3
Parameters
Apart from the condition that they must not vanish to give
a non-trivial solution and a non-singular solution with
non-vanishing denominators, the following parameters are free:
q12, p3, p1
Inequalities
In the following not identically vanishing expressions are shown.
Any auxiliary variables g00?? are used to express that at least
one of their coefficients must not vanish, e.g. g0019*p4 + g0020*p3
means that either p4 or p3 or both are non-vanishing.
{g0065*p3 + 5*g0068*p1,p1 + p3,g0078*p3 + g0080*p1,p3}
Relevance for the application:
The equation:
f =Df *f*p1 + Df*f *p3
t x x
The symmetry:
4 5
5*Df *(Df) *f*p1*q12 + (Df) *f *p3*q12
x x
f =----------------------------------------
s p3
And now in machine readable form:
The system:
df(f(1),t)=d(1,df(f(1),x))*f(1)*p1 + d(1,f(1))*df(f(1),x)*p3$
The symmetry:
df(f(1),s)=(5*d(1,df(f(1),x))*d(1,f(1))**4*f(1)*p1*q12 + d(1,f(1))**5*df(f(1),x)
*p3*q12)/p3$