Solution 4 to problem N1f1b0o24w1
Expressions |
Parameters |
Inequalities |
Relevance |
Back to problem N1f1b0o24w1
Expressions
The solution is given through the following expressions:
q13=0
q12=0
q11=0
q10=0
q9=0
q8=0
q7=0
q5=0
q3=0
q2=0
q1=0
p4=0
p2=0
3*p1*q6
p3=---------
q4
Parameters
Apart from the condition that they must not vanish to give
a non-trivial solution and a non-singular solution with
non-vanishing denominators, the following parameters are free:
q4, q6, p1
Inequalities
In the following not identically vanishing expressions are shown.
Any auxiliary variables g00?? are used to express that at least
one of their coefficients must not vanish, e.g. g0019*p4 + g0020*p3
means that either p4 or p3 or both are non-vanishing.
{g0027*p3 + 3*g0029*p1,p1,g0034*p3 + g0036*p1}
Relevance for the application:
The equation:
Df *f*p1*q4 + 3*Df*f *p1*q6
x x
f =-----------------------------
t q4
The symmetry:
2 3
f =Df *(Df) *f*q4 + (Df) *f *q6
s x x
And now in machine readable form:
The system:
df(f(1),t)=(d(1,df(f(1),x))*f(1)*p1*q4 + 3*d(1,f(1))*df(f(1),x)*p1*q6)/q4$
The symmetry:
df(f(1),s)=d(1,df(f(1),x))*d(1,f(1))**2*f(1)*q4 + d(1,f(1))**3*df(f(1),x)*q6$