Solution 3 to problem N1t4s10f1
Expressions |
Parameters |
Inequalities |
Relevance |
Back to problem N1t4s10f1
Expressions
The solution is given through the following expressions:
q21=0
q20=0
q19=0
q18=0
q17=0
q16=0
q15=0
q14=0
q13=0
q12=0
q11=0
q10=0
q9=0
q7=0
q6=0
q4=0
q3=0
q2=0
q1=0
p4=0
p2=0
p3*q5
q8=-------
4*p1
Parameters
Apart from the condition that they must not vanish to give
a non-trivial solution and a non-singular solution with
non-vanishing denominators, the following parameters are free:
q5, p1, p3
Inequalities
In the following not identically vanishing expressions are shown.
Any auxiliary variables g00?? are used to express that at least
one of their coefficients must not vanish, e.g. g0019*p4 + g0020*p3
means that either p4 or p3 or both are non-vanishing.
{g0041*p3 + 4*g0044*p1,p1,g0050*p3 + g0052*p1}
Relevance for the application:
The equation:
f =Df *f*p1 + Df*f *p3
t x x
The symmetry:
3 1 4
Df *(Df) *f*p1*q5 + ---*(Df) *f *p3*q5
x 4 x
f =----------------------------------------
s p1
And now in machine readable form:
The system:
df(f(1),t)=d(1,df(f(1),x))*f(1)*p1 + d(1,f(1))*df(f(1),x)*p3$
The symmetry:
df(f(1),s)=(d(1,df(f(1),x))*d(1,f(1))**3*f(1)*p1*q5 + 1/4*d(1,f(1))**4*df(f(1),x
)*p3*q5)/p1$