Solution 2 to problem N1t13s14f2
Expressions |
Parameters |
Inequalities |
Relevance |
Back to problem N1t13s14f2
Expressions
The solution is given through the following expressions:
q14=0
q11=0
q10=0
q9=0
q8=0
q7=0
q6=0
q5=0
q4=0
q3=0
q2=0
q1=0
p11=0
p10=0
p9=0
p8=0
p7=0
p5=0
p4=0
p3=0
p2=0
p1=0
Parameters
Apart from the condition that they must not vanish to give
a non-trivial solution and a non-singular solution with
non-vanishing denominators, the following parameters are free:
q13, q12, p6
Inequalities
In the following not identically vanishing expressions are shown.
Any auxiliary variables g00?? are used to express that at least
one of their coefficients must not vanish, e.g. g0019*p4 + g0020*p3
means that either p4 or p3 or both are non-vanishing.
{p6,g0006*q13 + g0007*q12}
Relevance for the application:
The equation:
f =Df*f *f *f*p6
t 2x x
The symmetry:
f =f *f *f*q12 + f *f *f*q13
s 4x x 3x 2x
And now in machine readable form:
The system:
df(f(1),t)=d(1,f(1))*df(f(1),x,2)*df(f(1),x)*f(1)*p6$
The symmetry:
df(f(1),s)=df(f(1),x,4)*df(f(1),x)*f(1)*q12 + df(f(1),x,3)*df(f(1),x,2)*f(1)*q13
$