Solution 1 to problem N1t2s6b2
Expressions |
Parameters |
Inequalities |
Relevance |
Back to problem N1t2s6b2
Expressions
The solution is given through the following expressions:
p1=0
Parameters
Apart from the condition that they must not vanish to give
a non-trivial solution and a non-singular solution with
non-vanishing denominators, the following parameters are free:
q6, q4, q3, q2, q1, q5, p2
Inequalities
In the following not identically vanishing expressions are shown.
Any auxiliary variables g00?? are used to express that at least
one of their coefficients must not vanish, e.g. g0019*p4 + g0020*p3
means that either p4 or p3 or both are non-vanishing.
{q5,p2}
Relevance for the application:
The equation:
b =b *p2
t x
The symmetry:
4 2 2
b =b *q4 + Db *Db*q5 + b *q6 + b *b*q1 + b *q3 + b *b *q2
s x 3x 2x x x
And now in machine readable form:
The system:
df(b(1),t)=df(b(1),x)*p2$
The symmetry:
df(b(1),s)=b(1)**4*q4 + d(1,df(b(1),x))*d(1,b(1))*q5 + df(b(1),x,3)*q6 + df(b(1)
,x,2)*b(1)*q1 + df(b(1),x)**2*q3 + df(b(1),x)*b(1)**2*q2$