Solution 1 to problem N1t2s4f1


Expressions | Parameters | Inequalities | Relevance | Back to problem N1t2s4f1

Expressions

The solution is given through the following expressions:

p1=0


Parameters

Apart from the condition that they must not vanish to give a non-trivial solution and a non-singular solution with non-vanishing denominators, the following parameters are free:
 q4, q3, q2, q1, p2

Inequalities

In the following not identically vanishing expressions are shown. Any auxiliary variables g00?? are used to express that at least one of their coefficients must not vanish, e.g. g0019*p4 + g0020*p3 means that either p4 or p3 or both are non-vanishing.
 
{g0009*q4 + g0010*q3 + g0011*q2 + g0012*q1,g0005*q3 + g0006*q2 + g0007*q1,p2}


Relevance for the application:



The equation: 


f =f *p2
 t  x
The symmetry:
                  2
f =Df *f*q1 + (Df) *f*q2 + Df*f *q3 + f  *q4
 s   x                         x       2x
And now in machine readable form:

The system:

df(f(1),t)=df(f(1),x)*p2$
The symmetry:
df(f(1),s)=d(1,df(f(1),x))*f(1)*q1 + d(1,f(1))**2*f(1)*q2 + d(1,f(1))*df(f(1),x)
*q3 + df(f(1),x,2)*q4$