Solution 1 to problem N1t2s5b1


Expressions | Parameters | Inequalities | Relevance | Back to problem N1t2s5b1

Expressions

The solution is given through the following expressions:

p1=0


Parameters

Apart from the condition that they must not vanish to give a non-trivial solution and a non-singular solution with non-vanishing denominators, the following parameters are free:
 q4, q3, q2, q1, q5, p2

Inequalities

In the following not identically vanishing expressions are shown. Any auxiliary variables g00?? are used to express that at least one of their coefficients must not vanish, e.g. g0019*p4 + g0020*p3 means that either p4 or p3 or both are non-vanishing.
 
{q5,p2}


Relevance for the application:



The equation: 


b =b *p2
 t  x
The symmetry:
    6                               2          3
b =b *q4 + Db *Db*q5 + b  *b*q1 + b  *q3 + b *b *q2
 s           x          2x         x        x
And now in machine readable form:

The system:

df(b(1),t)=df(b(1),x)*p2$
The symmetry:
df(b(1),s)=b(1)**6*q4 + d(1,df(b(1),x))*d(1,b(1))*q5 + df(b(1),x,2)*b(1)*q1 + df
(b(1),x)**2*q3 + df(b(1),x)*b(1)**3*q2$