Solution 4 to problem N1t8s10f1
Expressions |
Parameters |
Inequalities |
Relevance |
Back to problem N1t8s10f1
Expressions
The solution is given through the following expressions:
q21=0
q19=0
q18=0
q17=0
q16=0
q15=0
q14=0
q12=0
q11=0
q10=0
q9=0
q8=0
q7=0
q6=0
q5=0
q4=0
q3=0
q2=0
q1=0
p13=0
p11=0
p10=0
p9=0
p8=0
p7=0
p6=0
p5=0
p4=0
p3=0
p2=0
p1=0
Parameters
Apart from the condition that they must not vanish to give
a non-trivial solution and a non-singular solution with
non-vanishing denominators, the following parameters are free:
q13, q20, p12
Inequalities
In the following not identically vanishing expressions are shown.
Any auxiliary variables g00?? are used to express that at least
one of their coefficients must not vanish, e.g. g0019*p4 + g0020*p3
means that either p4 or p3 or both are non-vanishing.
{q20,p12,g0005*q20 + g0012*q13 + g0025*p12,g0038*q20 + g0045*q13}
Relevance for the application:
The equation:
f =f *f *f*p12
t 2x x
The symmetry:
f =Df*f *f *f*q13 + f *f *f*q20
s 2x x 3x x
And now in machine readable form:
The system:
df(f(1),t)=df(f(1),x,2)*df(f(1),x)*f(1)*p12$
The symmetry:
df(f(1),s)=d(1,f(1))*df(f(1),x,2)*df(f(1),x)*f(1)*q13 + df(f(1),x,3)*df(f(1),x)*
f(1)*q20$